The height of a cuboid is 18 m- Its length is 3 times its height and 2 times its width- Find the surface area of the cuboid-displaystyle 5280- m - 2 -displaystyle 5832- m - 2 -displaystyle 5313- m - 2 -displaystyle 5188- m - 2 -

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Toppr Admin · Accepted Answer

Surface area -2-xD7- -Length -xD7- width - Length -xD7- height - Width -xD7- height-Height -18 mLength -3-xD7- height -3-xD7-18-54 mWidth - Length2-542-27 m-2-xD7-1458-972-486-2-xD7-2916-5832 m2

The height of a cuboid is $18$ m. Its length is $3$ times its height and $2$ times its width. Find the surface area of the cuboid.
$5280 m^{2}$
$5832 m^{2}$
$5313 m^{2}$
$5188 m^{2}$

Surface area $= 2 \times$ $($ Length $\times$ width $+$ Length $\times$ height $+$ Width $\times$ height $)$
Height $= 18$ m
Length $= 3 \times$ height $= 3 \times 18 = 54$ m
Width $=$ $\frac{L e n g t h}{2} = \frac{54}{2} = 27$ m
$= 2 \times (1458 + 972 + 486)$
$= 2 \times 2916$
$= 5832$ $m^{2}$

The height of a cuboid is 18 m. Its length is 3 times its height and 2 times its width. Find the surface area of the cuboid.5280m25832m25313m25188m2

Surface area =2× (Length × width + Length × height + Width × height)Height =18 mLength =3× height =3×18=54 mWidth = Length2=542=27 m=2×(1458+972+486)=2×2916=5832 m2

The height of a cuboid is $18$ m. Its length is $3$ times its height and $2$ times its width. Find the surface area of the cuboid.
$5280 m^{2}$
$5832 m^{2}$
$5313 m^{2}$
$5188 m^{2}$

Surface area $= 2 \times$ $($ Length $\times$ width $+$ Length $\times$ height $+$ Width $\times$ height $)$
Height $= 18$ m
Length $= 3 \times$ height $= 3 \times 18 = 54$ m
Width $=$ $\frac{L e n g t h}{2} = \frac{54}{2} = 27$ m
$= 2 \times (1458 + 972 + 486)$
$= 2 \times 2916$
$= 5832$ $m^{2}$