Question

The heights of two vertical poles, above the earth's surface, are $$14 \dfrac{1}{2}$$ m and $$22 \dfrac{1}{3}$$ m respectively. How much higher is the second pole as compared with the height of the first pole?

Answer 1

It is given that
Height of first pole above the earth's surface $$=14 \dfrac{1}{2}$$ m
Height of second pole above the earth's surface $$=22 \dfrac{1}{3}$$ m
So height of second pole when compared to first pole =
$$22 \dfrac{1}{3}$$ m $$-14 \dfrac{1}{2}$$ m
We can write it as
$$= 67/3 - 29/2$$
LCM of 3 and 2 is 6
$$= \left(134 - 87 \right)/6$$
By further calculation
$$\dfrac{47}{6}=7\dfrac{5}{6}m$$