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Question

The hybrid state of $B$ in $B F_{4}^{-}$ is:
$s p^{2}$
not specific
$s p$
$s p^{3}$

A

not specific

B

s p^{2}

C

s p^{3}

D

s p

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Solution

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${B F}_{4}^{-}$ has $4$ bond pairs and $0$ lone pairs making it $s p^{3}$ hybridised.

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