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The hybrid states of central atom in diborane, diamond and graphite are respectively :- 1 sp2, sp3, sp2 2sp3, sp3, sp2 3 sp?, sp, sp3 sp, sp?, sp3

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Similar Questions

Q1

select the correct state of hybridization at $$X_1, X_2, X_3 and X_4$$
$$X_1$$ $$X_2$$ $$X_3$$ $$X_4$$
(a) $$sp^2$$ $$sp$$ $$sp^2$$ $$sp^3$$
(b) $$sp^3$$ $$sp^2$$ $$sp$$ $$sp$$
(c) $$sp^2$$ $$sp^2$$ $$sp$$ $$sp^3$$
(d) $$sp^3$$ $$sp^2$$ $$sp^2$$ $$sp$$

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Q2

The order of electro negativity of carbon in

s p, s p^{2} a n d s p^{3}

hybridized states follows

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Q3

21.The correct order regarding the electronegativity of hybrid orbitals of carbon is 1) sp< sp2< sp3 2) sp> sp2 < sp3 3) sp> sp2 > sp3 4) sp< sp2 > sp3

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Q4

The hybridization present in

C H_{4}, C_{2} H_{6}, a n d C_{2} H_{4}

are respectively:

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Q5

The hybridisation of orbitals of N atom in

N O_{3}^{-}, N O_{2}^{+} a n d N H_{4}^{+}

are respectively

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