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Question

The increasing order of basicity of the given compounds is:
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  1. (b)< (a)< (d)< (c)
  2. (b)< (a)< (c)< (d)
  3. (d)< (b)< (a)< (c)
  4. (a)< (b)< (c)< (d)

A
(b)< (a)< (d)< (c)
B
(d)< (b)< (a)< (c)
C
(a)< (b)< (c)< (d)
D
(b)< (a)< (c)< (d)
Solution
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Order of base nature depends on electron donation tendency.
In compound (b) nitrogen is sp2 hybridized so least basic among all given compound
Compound (C) is a very strong nitrogeneous organic base as a lone pair of one nitrogen delocalize in resonance and make another nitrogen negatively charged and conjugate acid have two equivalent resonating structure.
Thus it is most basic in given compound.
Compound (d) is secondary amine more basic than compound (a) which is a primary amine.
Therefore, increasing order of basicity is
(b) < (a) < (d) < (c)


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