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Question

The internal bisector of an angle of a triangle divides the opposite side internally in the ratio of the sides containing the angle.

  1. True
  2. False

A
True
B
False
Solution
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Consider an isosceles triangle ABC, with AB = AC. BD and CE are median on AC and AB respectively.
Now, AB=AC
12AB=12AC
BE=CD (I)

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Similar Questions
Q1
The internal bisector of an angle of a triangle divides the opposite side internally in the ratio of the sides containing the angle.

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Q2
Prove that the internal bisector of an angle of a triangle divides the opposite side internally in the ratio of the sides containing the angle.
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Q3
The internal bisector of an angle of a triangle divides the opposite side internally in the ratio of the corresponding sides containing the angle. Prove it.
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Q4

Assertion (A): If one angle of a triangle is equal to one angle of another triangle and bisectors of these angles divide the opposite sides in the same ratio, then the triangles are similar.
Reason (R): The internal bisector of an angle of a triangle divides the opposite side internally in the ratio of the sides containing the angle.

Which of the following is true?


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Q5
In a triangle, angle bisector of a vertex divides the opposite side in the ratio of remaining sides of the triangle.
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