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Coordination Number

Question

The ionic radii of $A^{+}$ and $B^{-}$ ions are $0.98 \times 10^{- 10} m$ and $1.81 \times 10^{- 10} m$ . The coordination number of each ion in $A B$ is:
6
4
8
2

A

8

B

6

C

4

D

2

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Solution

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The radius ratio

$\frac{r_{A^{+}}}{r_{B^{-}}} = \frac{0.98 \times 10^{- 10}}{1.81 \times 10^{- 10}} = 0.54$

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Similar Questions

Q1

The ionic radii of

A^{+}

and

B^{-}

ions are

0.98 \times 10^{- 10} m

and

1.81 \times 10^{- 10} m .

The coordination number of each ion in

A B

is:

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Q2

The ionic radii of $A^{+}$ and $B^{-}$ ions are $0.98 \times 10^{- 10} m$ and $1.81 \times 10^{- 10} m$ . The coordination number of each ion in AB is

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Q3

Ionic radii of

M g^{2 +}

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ions are

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140

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M g^{2 +}

ion are :

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Q4

The radius of

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. The a\coordination number of

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Q5

The ionic radii for

N a^{+}

and

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ions are

1.012

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is predicted on the basis of the radii ratio,

\frac{r_{+}}{r_{-}}

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