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Question

The ionisation potential of X(g) is numerically equal to :
  1. E.A. of X(g)
  2. EA of X+(g)
  3. E.A. of X2(g)
  4. E.A of X2+(g)

A
E.A. of X(g)
B
EA of X+(g)
C
E.A of X2+(g)
D
E.A. of X2(g)
Solution
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XX+e; ΔH=I.P of X
X+eX; ΔH=E.A of X
Comparing the above two equations we get :
I.P of X=E.A of X

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Q1
Assign true (T) or false (F) for the following statements and select the correct option for your answer.
I) I.P. of O(g) is less than I.P. of O(g)
II) I.P. of Ne(g) is greater than I.P. of Ne+(g)
III) E.A. of O+(g) is greater than E.A. of O(g)
IV) E.A. of N(g) is greater than I.P. of N+(g)
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Q2
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Q3
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Q4
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Q5

​​​​​​

No/2 atoms of X(g) are converted into X+(g) by energy E1 ​​​. No/2 atoms of X(g) are converted into X-(g) by energy E2 ​​​​​​. Hence the ionisation potential and electron affinity of X(g) per atom are:

A. 2E1/No. , 2(E2-E1)/No

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C. E1-E2/No. ,. 2E2/No

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