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Correct option is C)

Bohr's model is used to solve this question,

According to this $E=−13.6×n_{2}Z_{2} $

So, in this the E is equal to energy of electron in $n_{th}$ shell of atom whose atomic number is Z

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Now, same amount of energy with opposite sign must be given to electron in order to remove it. $I.E.=−13.6×Z_{2}eV$ (As n=1)

Since for Lithium, Z=3

Therefore, you get $I.E.=−122.4eV$

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