The jogging track in circumference-Deepak and his wife start from the same point and walk in opposite directions 4-5 km-hr and 3-75 km-hr respectively-They will meet the first time in

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Clearly they will meet 726 m apart- To be -4-5-3-75-8-25 m apart they take themTo be apart they take-xA0-100825-xD7-7261000-5-28 min-

The jogging track in circumference.Deepak and his wife start from the same point and walk in opposite directions at 4.5 km/hr and 3.75 km/hr respectively.They will meet for the first time in

Clearly they will meet $726$ m apart. To be $(4.5 + 3.75) = 8.25$ m apart they take them
To be apart they take $= (\frac{100}{825} \times \frac{726}{1000}) = 5.28$ min.

The jogging track in circumference.Deepak and his wife start from the same point and walk in opposite directions at 4.5 km/hr and 3.75 km/hr respectively.They will meet for the first time in

Clearly they will meet 726 m apart. To be (4.5+3.75)=8.25 m apart they take themTo be apart they take =(100825×7261000)=5.28 min.

Clearly they will meet $726$ m apart. To be $(4.5 + 3.75) = 8.25$ m apart they take them
To be apart they take $= (\frac{100}{825} \times \frac{726}{1000}) = 5.28$ min.