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Question

The Kolbe's electrolysis of potassium succinate gives $C O_{2}$ and _______.
ethene
methane
ethane
methanol

A

ethane

B

methanol

C

ethene

D

methane

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Solution

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The Kolbe reaction is formally a decarboxylative dimerisation of two carboxylic acids (or carboxylate ions) The overall general reaction is

$2 R - C O O^{-} \to R - R + 2 C O_{2} + 2 e^{-}$

In dicarboxylates the intramolecular bonding produces alkene.

Potassium succinate results in formation of ethene by Kolbe electrolysis.

Option A is correct.

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