The least count of a stop watch is 0.2 s. The time of 20 oscillations of a pendulum is measured to be 25 s. The percentage error in the measurement of time will be:
16 %
0.8 %
1.8 %
0.1 %
A
16 %
B
0.8 %
C
1.8 %
D
0.1 %
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Solution
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Number of oscillations n=20
Time taken =25s
∴ Time period of oscillation T=2520=1.25s
Given : Error in time for 20 oscillations,ΔT=0.2s Hence error in time for 1 oscilations, ΔT′=0.2n=s
∴ Percentage error =ΔTT×100=0.220×1.25×100=0.8%
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