Let the length and breadth is 7x and 4x of the field (given ratio of length and breadth is 7:4)
If 4 m path is outside field made
then breadth =4x and length is 7x+4+4=7x+8
Then thje area of path =2(4x×4)+2[(4x+8)4]
But path area given 416 sq m
Then 2(4x×4)+2[(4x+8)4]=416⇒32x+56x+64=416⇒56x=352⇒x=4
Then length=7×4=28 m and breadth=4×4=16 m