The length of a rectangle is increased by $a = 30 %$ and breadth is decreased by $b = 25 %$ . What is the percentage change in the area of the rectangle?

Question

The length of a rectangle is increased by 10-  while its breadth is decreased by 10- - What is the consequent percentage change in the area of the rectangle-

Toppr Admin · Accepted Answer

As length is increased by 10- and breadth is decreased by 10-Then new area will be-110-l-xD7-90-xD7-b-99-lbSo- change-100-x2212-99-1-

The length of a rectangle is increased by $10 %$ while its breadth is decreased by $10 %$ . What is the consequent percentage change in the area of the rectangle?

As length is increased by $10 %$ and breadth is decreased by $10 %$
Then new area will be $= 110 % l \times 90 % \times b = 99 % l b$
So, $%$ change $= 100 % - 99 % = 1 %$

The length of a rectangle is increased by 10% while its breadth is decreased by 10%. What is the consequent percentage change in the area of the rectangle?

As length is increased by 10% and breadth is decreased by 10%Then new area will be=110%l×90%×b=99%lbSo,% change=100%−99%=1%

The length of a rectangle is increased by $10 %$ while its breadth is decreased by $10 %$ . What is the consequent percentage change in the area of the rectangle?

As length is increased by $10 %$ and breadth is decreased by $10 %$
Then new area will be $= 110 % l \times 90 % \times b = 99 % l b$
So, $%$ change $= 100 % - 99 % = 1 %$