The length of a thin wire require to manufacture a solenoid of length l=100 cm and inductance L=1mH, if the solenoid's cross-sectional diameter is considerably less than its length is:
1km
0.10km
10km
0.010km
A
1km
B
0.10km
C
10km
D
0.010km
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Solution
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Let l1 is the length of wire, l1=2πrN⇒Nr=l12π⇒L=μ0πr2N2l=μ0πll214π2 ⇒l1=√Ll4πμ0=√10−3×1×4π4π×10−7=102m=0.10km
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