The length of simple pendulum is 1m and mass of its bob is $50$ gram. The bob is given sufficient velocity so that the bob describes vertical circle whose radius equal to length of pendulum. The maximum difference in the kinetic energy of bob during one revolution is:

Question

The length of simple pendulum is 1m and mass of its bob is

50

gram. The bob is given sufficient velocity so that the bob describes vertical circle whose radius equal to length of pendulum. The maximum difference in the kinetic energy of bob during one revolution is:

Toppr Admin · Accepted Answer

Using conservation of energy-xA0-mg-xD7-2R-mv2-2v-2-x221A-Rg -1-At lower most point- from free body digram-T-x2212-mg-mv2-R -2-From -1- and -2-xA0-T-5mgT-2-5N

The length of simple pendulum is $1 m$ and mass of its bob is $50 g r a m$ . The bob is given sufficient velocity so that the bob describes vertical circle whose radius equal to length of pendulum, the tension in the string at lowest extreme position is:
$2.5 N$
$1 N$
$1.5 N$
$2 N$

Using conservation of energy,
$m g \times 2 R = m v^{2} / 2$
$v = 2 \sqrt{R g}$ .........(1)

At lower most point, from free body digram,
$T - m g = m v^{2} / R$ ...........(2)
From (1) and (2),
$T = 5 m g$
$T = 2.5 N$

The length of simple pendulum is 1m and mass of its bob is 50gram. The bob is given sufficient velocity so that the bob describes vertical circle whose radius equal to length of pendulum, the tension in the string at lowest extreme position is:2.5N1N1.5N2N

Using conservation of energy, mg×2R=mv2/2v=2√Rg .........(1)At lower most point, from free body digram,T−mg=mv2/R ...........(2)From (1) and (2), T=5mgT=2.5N

The length of simple pendulum is $1 m$ and mass of its bob is $50 g r a m$ . The bob is given sufficient velocity so that the bob describes vertical circle whose radius equal to length of pendulum, the tension in the string at lowest extreme position is:
$2.5 N$
$1 N$
$1.5 N$
$2 N$

Using conservation of energy,
$m g \times 2 R = m v^{2} / 2$
$v = 2 \sqrt{R g}$ .........(1)

At lower most point, from free body digram,
$T - m g = m v^{2} / R$ ...........(2)
From (1) and (2),
$T = 5 m g$
$T = 2.5 N$