Question

The length of the rod is 150 cm at ${25}^{o}C$Find its length when it is heated ${150}^{o}C$ ($\alpha$ steel = $2.2\times {10}^{-5}{/}^{o}C$)

Answer 1

We know that$,$

$L=L_0\left(1+\alpha \Delta T\right)$

$L_0$ length at ${25}^{0}C=150cm$

$\alpha =$ linear expansion coefficient$=2.2\times {10}^{-5}{/}^{0}C$

$\Delta T=\left(150-25\right)={125}^{0}C$

$L=150\times \left(1+2.2\times {10}^{-5}\times 125\right)$

$=150\times 1.00275$

$=150.4125cm$

We get,

$L=150.4125cm$