The length of the simple pendulum which ticks seconds is:
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The correct option is B1m The time period of a simple pendulum is T=2π√Lg where L is the length of the pendulum. or L=gT24π2 The time period of the simple pendulum which ticks seconds is 2s. ∴T=2s Substituting in (i), we get
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A hollow sphere of mass m = 1 kg and radius R = 1m rests on a smooth horizontal surface. A simple pendulum having string of length R and bob of mass m = 1 kg hangs from top most point of the sphere as shown in the figure. A bullet of mass m = 1 kg and velocity v = 2m/sec partially penetrates the left side of the sphere. The velocity of the sphere just after collision with bullet is:
The length of a seconds' pendulum is nearly :
(a) 0.5 m (b) 9.8 m
(c) 1.0 m (d) 2.0 m.
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