The length of the simple pendulum which ticks seconds is:

Question

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Answer 1

The time period of a simple pendulum is
$T = 2 π \frac{L}{g}$
where L is the length of the pendulum.
or $L = \frac{g T ^{2}}{4 π ^{2}}$
The time period of the simple pendulum which ticks seconds is $2$ s.
$∴ T = 2 s$
Substituting in (i), we get

$L = \frac{( 9 . 8 m s ^{- 2} ) ( 2 s ) ^{2}}{4 \times ( 3 . 1 4 ) ^{2}} = 1 m$

Answer 2

The time period of a simple pendulum is

T = 2 π \frac{L}{g}

where L is the length of the pendulum.
or

L = \frac{g T ^{2}}{4 π ^{2}}

The time period of the simple pendulum which ticks seconds is

2

s.

∴ T = 2 s

Substituting in (i), we get

L = \frac{( 9 . 8 m s ^{- 2} ) ( 2 s ) ^{2}}{4 \times ( 3 . 1 4 ) ^{2}} = 1 m