The linear charge density of four quadrants of a ring of radius R is as shown. Electric field at the centre will be :

Zero
$\frac{2 \sqrt{K} λ}{R}$
$\frac{4 \sqrt{2} K λ}{R}$
$\frac{4 K λ}{R}$

Question

The linear charge density of four quadrants of a ring of radius R is as shown- Electric field the centre will be -Zerofrac -2sqrt Klambda-R-frac -4sqrt 2Klambda-R-frac -4Klambda-R-

Toppr Admin · Accepted Answer

Field due to a semicircular uniform charge is 2K-x3BB-RThus field at center due this configuration is 4K-x3BB-R

The linear charge density of four quadrants of a ring of radius R is as shown. Electric field at the centre will be :Zero2√KλR4√2KλR4KλR

Field due to a semicircular uniform charge is 2KλRThus field at center due this configuration is 4KλR

The linear charge density of four quadrants of a ring of radius R is as shown. Electric field at the centre will be :

Zero
$\frac{2 \sqrt{K} λ}{R}$
$\frac{4 \sqrt{2} K λ}{R}$
$\frac{4 K λ}{R}$

Field due to a semicircular uniform charge is $\frac{2 K λ}{R}$
Thus field at center due this configuration is $\frac{4 K λ}{R}$