The linear momentum P of a body varies with time and is given by the equation P - x - yt-2 where x and y are constants- The net force acting on the body a one-dimensional motion is proportional to-dfrac -1-t-tt-2a constant

Question

The linear momentum P of a body varies with time and is given by the equation P - x - yt-2 where x and y are constants- The net force acting on the body a one-dimensional motion is proportional to-dfrac -1-t-tt-2a  constant

Toppr Admin · Accepted Answer

P-x-yt2F-dPdt-2yt-x221D-t

The linear momentum $P$ of a body varies with time and is given by the equation $P = x + y t^{2}$ where $x$ and $y$ are constants. The net force acting on the body for a one-dimensional motion is proportional to:
$\frac{1}{t}$
$t$
$t^{2}$
$a c o n s t a n t$

$P = x + y t^{2}$
$F = \frac{d P}{d t} = 2 y t \propto t$

The linear momentum P of a body varies with time and is given by the equation P=x+yt2 where x and y are constants. The net force acting on the body for a one-dimensional motion is proportional to:1ttt2a constant

P=x+yt2F=dPdt=2yt∝t

The linear momentum $P$ of a body varies with time and is given by the equation $P = x + y t^{2}$ where $x$ and $y$ are constants. The net force acting on the body for a one-dimensional motion is proportional to:
$\frac{1}{t}$
$t$
$t^{2}$
$a c o n s t a n t$

$P = x + y t^{2}$
$F = \frac{d P}{d t} = 2 y t \propto t$