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# The magnetic field at a point associated with a light wave is B=2×10−8 Tesla sin[(3.0×1015s−1)t]sin[(6.0×1015s−1)t]. If this light falls on a metal surface having a work function of 2.0 eV, what will be the maximum kinetic energy of the photo-electrons?

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Q1

The electric field at a point associated with a light wave is E = (100 Vm 1) sin [(3.0 ×1015s1)t] sin [(6.0×1015s1)t]. If this light falls on a metal surface having a work function of 2.0 eV, what will be the maximum kinetic energy of the photo electrons ?

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Q2
The electric field at a point associated with a light wave is
$E=\left(100{\mathrm{Vm}}^{-1}\right)\mathrm{sin}\left[\left(3.0×{10}^{15}{s}^{-1}\right)t\right]\mathrm{sin}\left[\left(6.0×{10}^{15}{s}^{-1}\right)t\right].$
If this light falls on a metal surface with a work function of 2.0 eV, what will be the maximum kinetic energy of the photoelectrons?
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Q3
The electric field at a point associated with a light wave is

If this light falls on a metal surface with a work function of 2.0 eV, what will be the maximum kinetic energy of the photoelectrons?
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Q4
Light described at a place by the equation E=(100V/M)×[sin(5×1015s1)t+sin(8×1015s1)t]
Falls on a metal surface having work function 2.0 e.V Calculate the maximum kinetic energy of the photoelectrons
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Q5
At a place, a light wave described by the equation E=(100Vm)[sin (2π×1015s1)t+sin(3π×1015s1)t], where t is in seconds, falls on a metal surface having work function 2.1eV. The maximum kinetic energy of the emitted photoelectrons( in eV) is nearly.
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