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# The magnetic field at a point associated with a light wave is B=2×10−8 Tesla sin[(3.0×1015s−1)t]sin[(6.0×1015s−1)t]. If this light falls on a metal surface having a work function of 2.0 eV, what will be the maximum kinetic energy of the photo-electrons?

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Q1

The electric field at a point associated with a light wave is E = (100 Vm 1) sin [(3.0 ×1015s1)t] sin [(6.0×1015s1)t]. If this light falls on a metal surface having a work function of 2.0 eV, what will be the maximum kinetic energy of the photo electrons ?

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Q2

At a place, a light wave described by the equation E=(100Vm)[sin (2π×1015s1)t+sin(3π×1015s1)t], where t is in seconds, falls on a metal surface having work function 2.1eV. The maximum kinetic energy of the emitted photoelectrons( in eV) is nearly.

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Q3

At a place, a light wave described by the equation E=(100Vm)[sin (2π×1015s1)t+sin(3π×1015s1)t], where t is in seconds, falls on a metal surface having work function 2.1eV. The maximum kinetic energy of the emitted photoelectrons( in eV) is nearly.

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Q4

The magnetic field associated with a light waves given at the origin by B=B0[sin(3.14×107) ct+sin(6.28×107) ct]
If this light falls on a silver plate having a work function of 4.7 eV, What will be the maximum kinetic energy of the photoelectrons?

(c=3×108 ms1,h=6.6×1034 J-s)

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Q5

The electric field at a point associated with a light wave is given by
E=200[sin(6×1015)t+sin(9×1015)t] Vm1
Given :h=4.14×1015 eVs
If this light falls on a metal surface having a work function of 2.50 eV, the maximum kinetic energy of the photoelectrons will be

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