The magnetic induction field strength due to a short bar magnet at a distance 0.20 m on the equatorial line is 20x10 $^{- 6}$ tesla. The magnetic moment of the bar magnet is

Question

The magnetic induction field strength due to a short bar magnet a distance 0-20 m on the equatorial line is 20x10-6- tesla- The magnetic moment of the bar magnet is3-2A-m-2-6-4A-m-2-1-6A-m-2-16A-m-2-

Toppr Admin · Accepted Answer

Magnetic field at the equator is-B-equatorial- -x2212-x3BC-0m4-x3C0-d320-xD7-156-2-xD7-4-x3C0-xD7-10-x2212-7-xD7-m4-x3C0-xD7-0-2-3m-1-6Am-

The magnetic induction field strength due to a short bar magnet at a distance 0.20 m on the equatorial line is 20x10 $^{- 6}$ tesla. The magnetic moment of the bar magnet is
3.2A.m $^{2}$
6.4A.m $^{2}$
1.6A.m $^{2}$
16A.m $^{2}$

Magnetic field at the equator is,
B(equatorial) $= \frac{- μ_{0} m}{4 π d^{3}}$
$20 \times 15^{6} = \frac{2 \times 4 π \times 10^{- 7} \times m}{4 π \times (0.2)^{3}}$
$m = 1.6 A m .$

The magnetic induction field strength due to a short bar magnet at a distance 0.20 m on the equatorial line is 20x10−6 tesla. The magnetic moment of the bar magnet is3.2A.m26.4A.m21.6A.m216A.m2

Magnetic field at the equator is,B(equatorial) =−μ0m4πd320×156=2×4π×10−7×m4π×(0.2)3m=1.6Am.

The magnetic induction field strength due to a short bar magnet at a distance 0.20 m on the equatorial line is 20x10 $^{- 6}$ tesla. The magnetic moment of the bar magnet is
3.2A.m $^{2}$
6.4A.m $^{2}$
1.6A.m $^{2}$
16A.m $^{2}$

Magnetic field at the equator is,
B(equatorial) $= \frac{- μ_{0} m}{4 π d^{3}}$
$20 \times 15^{6} = \frac{2 \times 4 π \times 10^{- 7} \times m}{4 π \times (0.2)^{3}}$
$m = 1.6 A m .$