The magnetic poles placed in air repel each other with a force of $4 \times 10^{- 6} N$ . When the space between them is filled with a medium the repulsive force becomes $2.24 \times 1 0^{- 5} N$ . The relative permeability of the medium is

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F-4-xD7-10-x2212-6NFnew-2-24-xD7-10-x2212-5F-xD7-M2-Fnew-xA0-xA0-xA0- Here M is the permeability-M2-2-24-xD7-10-x2212-54-xD7-10-x2212-6M2-5-6

The magnetic poles placed in air repel each other with a force of $4 \times 10^{- 6} N$ . When the space between them is filled with a medium the repulsive force becomes $2.24 \times 1 0^{- 5} N$ . The relative permeability of the medium is

$\frac{5}{28}$
$5.6$
$8.96 \times 10^{- 11}$
$56$

$F = 4 \times 10^{- 6} N$
$F_{n e w} = 2.24 \times 10^{- 5}$
$F \times M_{2} = F_{n e w}$ Here M is the permeability.
$M_{2} = \frac{2.24 \times 10^{- 5}}{4 \times 10^{- 6}}$
$M_{2} = 5.6$

The magnetic poles placed in air repel each other with a force of 4×10−6N. When the space between them is filled with a medium the repulsive force becomes 2.24×10−5N. The relative permeability of the medium is5285.68.96×10−1156

F=4×10−6NFnew=2.24×10−5F×M2=Fnew Here M is the permeability.M2=2.24×10−54×10−6M2=5.6

The magnetic poles placed in air repel each other with a force of $4 \times 10^{- 6} N$ . When the space between them is filled with a medium the repulsive force becomes $2.24 \times 1 0^{- 5} N$ . The relative permeability of the medium is

$\frac{5}{28}$
$5.6$
$8.96 \times 10^{- 11}$
$56$

$F = 4 \times 10^{- 6} N$
$F_{n e w} = 2.24 \times 10^{- 5}$
$F \times M_{2} = F_{n e w}$ Here M is the permeability.
$M_{2} = \frac{2.24 \times 10^{- 5}}{4 \times 10^{- 6}}$
$M_{2} = 5.6$