The magnifying power of an astronomical telescope is 8, then the ratio of the focal length of the objective to the focal length of the eyepiece is : (final image is at ∞)
8
18
0.45
None of these
A
None of these
B
8
C
18
D
0.45
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Solution
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Magnifying power of telescope (M P)=8 The magnifying power of an astronomical telescope is =focallengthofobject(−f0)focallengthofeyepiece(fe)=8 Hence, the ratio of the focal length of the objective to the focal length of the eyepiece is 8.
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