The magnitude of force per unit length on a wire carrying current I at O due to two semi infinite wires as shown in figure, (if the distance between the long parallel segments of the wire being equal to L and current in them is I) is:
A
πL+μ0I2j^
B
L−μ0I2j^
C
2Lμ0I2j^
D
Lμ0I2j^
Hard
Open in App
Solution
Verified by Toppr
Correct option is A)
Net Magnetic field at point O due to both the wires shall be B=−2∫900002πlμ0Isinθdθ along −k
∴B=−πlμ0I along −k
Now, F=I(dl×B) Where, dl is along i Therefore, dlF=πlμI2 along j
Solve any question of Moving Charges and Magnetism with:-