The mass and energy equivalent to 1 amu are respectively1-67times - 10 - -27 -gm- 9-30 MeV1-67times - 10 - -27 -kg- 930 MeV1-67times - 10 - -34 -kg- 1 MeV1-67times - 10 - -27 -kg- 1 MeV

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Toppr Admin · Accepted Answer

1 amuIt is defined as one twelfth of the mass of an unbound neutral atom of carbon-12 in its nuclear and electronic ground state-Mass of 1 mole C atoms -12gms1-xA0-amu-1212-xD7-6-023-xD7-1023-1-66-xD7-10-x2212-27kg

The mass and energy equivalent to $1 a m u$ are respectively
$1.67 \times 10^{- 27} g m$ , $9.30 M e V$
$1.67 \times 10^{- 27} k g$ , $930 M e V$
$1.67 \times 10^{- 34} k g$ , $1 M e V$
$1.67 \times 10^{- 27} k g$ , $1 M e V$

1 amu
It is defined as one twelfth of the mass of an unbound neutral atom of carbon-12 in its nuclear and electronic ground state.

Mass of 1 mole C atoms $= 12 g m s$
$1 a m u =$ $\frac{12}{12 \times 6.023 \times 10^{23}} = 1.66 \times 10^{- 27} k g$

The mass and energy equivalent to 1amu are respectively1.67×10−27gm, 9.30MeV1.67×10−27kg, 930MeV1.67×10−34kg, 1MeV1.67×10−27kg,1MeV

1 amuIt is defined as one twelfth of the mass of an unbound neutral atom of carbon-12 in its nuclear and electronic ground state.Mass of 1 mole C atoms =12gms1 amu=1212×6.023×1023=1.66×10−27kg

The mass and energy equivalent to $1 a m u$ are respectively
$1.67 \times 10^{- 27} g m$ , $9.30 M e V$
$1.67 \times 10^{- 27} k g$ , $930 M e V$
$1.67 \times 10^{- 34} k g$ , $1 M e V$
$1.67 \times 10^{- 27} k g$ , $1 M e V$

1 amu
It is defined as one twelfth of the mass of an unbound neutral atom of carbon-12 in its nuclear and electronic ground state.

Mass of 1 mole C atoms $= 12 g m s$
$1 a m u =$ $\frac{12}{12 \times 6.023 \times 10^{23}} = 1.66 \times 10^{- 27} k g$