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Updated on : 2022-09-05

Solution

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Correct option is C)

Sun mass $M_{s}=1.99×10_{38}$

distance $r=7.8×10_{11}$ all in $SI$ system of units

the centripetal force $(M_{j}v_{2}/r)$ for revolution will be provided by the gravitational attraction $GM_{j}M_{s}/r_{2}$

so equating both we get $M_{j}v_{2}/r=GM_{j}M_{s}/r_{2}$ which give us $v=2rGM_{s} $

after putting $G=6.67×10_{−11}Nm_{2}/(Kg)_{2}$ and other values

we get $v=1.3×10_{8}m/s$

Option C is correct.

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