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The mass of the Jupiter is 1.9×1027 kg and that of the sun is 1.99×1038 kg. The mean distance of the Jupiter from the sun is 7.8×1011 m. Speed of the Jupiter is (assuming that Jupiter moves in the circular orbit around the sun).
  1. 1.304×104 m/sec
  2. 13.04×104 m/sec
  3. 1.304×108 m/sec
  4. 1.304×102 m/sec

A
1.304×104 m/sec
B
13.04×104 m/sec
C
1.304×108 m/sec
D
1.304×102 m/sec
Solution
Verified by Toppr

Jupiter mass Mj=1.9×1027
Sun mass Ms=1.99×1038
distance r=7.8×1011 all in SI system of units

the centripetal force (Mjv2/r) for revolution will be provided by the gravitational attraction GMjMs/r2

so equating both we get Mjv2/r=GMjMs/r2 which give us v=2GMsr
after putting G=6.67×1011Nm2/(Kg)2 and other values
we get v=1.3×108m/s
Option C is correct.

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