The maximum displacement of a particle executing SHM from its mean position is 2 cm and its time period is 1 s. The equation of its displacement will be

A

$x=2sin4πt$

B

$x=2sin2πt$

C

$x=sin2πt$

D

$x=4sin2πt$

Medium

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Updated on : 2022-09-05

Solution

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Correct option is B)

Max. displacement = Amplitude = 2cm, thus it's of the form $x=2sinωt$ (assuming initial phase as 0) Now, $ω=2π/T=2π/1=2π$ Thus, $x=2sin2πt$