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# The maximum displacement of a particle executing SHM from its mean position is 2 cm and its time period is 1 s. The equation of its displacement will bex=2sin4πtx=2sin2πtx=sin2πtx=4sin2πt

A
x=sin2πt
B
x=2sin4πt
C
x=2sin2πt
D
x=4sin2πt
Solution
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#### Max. displacement = Amplitude = 2cm, thus it's of the form x=2sinωt (assuming initial phase as 0)Now, ω=2π/T=2π/1=2πThus, x=2sin2πt

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