The maximum displacement of a particle executing SHM from its mean position is 2 cm and its time period is 1 s. The equation of its displacement will be

x=2sin4πt

x=2sin2πt

x=sin2πt

x=4sin2πt

A

x=sin2πt

B

x=2sin4πt

C

x=2sin2πt

D

x=4sin2πt

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Solution

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Max. displacement = Amplitude = 2cm, thus it's of the form x=2sinωt (assuming initial phase as 0) Now, ω=2π/T=2π/1=2π Thus, x=2sin2πt

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