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Updated on : 2022-09-05

Solution

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Correct option is D)

In front of one of the slits,

$x=2d $ but $d=5λ$

$x=25λ $ and $D=10d=50λ$

Now, from equation (i), we have:

$Δx=25λ ×50λ5λ =4λ $

So, corresponding phas defference:

$ϕ=λ2π .(Δx)=λ2π ×4λ =2π $

As, $I=I_{0}cos_{2}(2ϕ )$

So, $I=I_{0}cos_{2}(4π )=2I_{0} $

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