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An maximum number of points of intersection of $8 c m^{2}$ .
$8$
$16$
$28$
$56$

A

28

B

56

C

8

D

16

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Solution

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The maximum number of points of intersection of $8$ straight lines is equal to selecting $2$ straight lines from $8$ because we can get a point of intersection when $2$ straight line intersect.
So, maximum number of points $=^{8} C_{2} = 28$

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