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Question

The maximum velocity of a particle performing linear S.H.M. is 0.16 m/s and its maximum acceleration is 0.64 m/s2. The calculate its time period
  1. 1.571 s
  2. 16 s
  3. 0.08 s
  4. 3.2 s

A
1.571 s
B
3.2 s
C
0.08 s
D
16 s
Solution
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Given,
vmax=0.16m/s
amax=0.64m/s2
Time period, T=?

In S.H.M, we know that
vmax=Aω. . . . . . .(1)
amax=Aω2. . . . . . (2)
amaxvmax=ω=2πT

T=2π×vmaxamax

T=2×3.14×0.160.64
T=1.57s
The correct option is A.

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