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the mid-point of hypotenuse AB. C is joined to \( \mathbf { M } \) and produced to a point \( D \) such that \( \mathrm { DM } = \mathrm { CM } . \) Point \( \mathrm { D } \) is joined to point \( \mathrm { B } \) (see Fig. 7.23 ). Show that (i) \( \Delta \mathrm { AMC } \cong \Delta \mathrm { BMD } \) (ii) \( \angle \mathrm { DBC } \) is a right angle (ui) \( \Delta \mathrm { DBC } \cong \Delta \mathrm { ACB } \)
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Q1
In right triangle ABC, right angled at C,M is the mid-point of hypotenuse AB. C is joined to M and produced to a point D such that DM=CM. Point D is joined to point B (see figure). Show that: (i) ΔAMC≅ΔBMD (ii) ∠DBC is a right angle. (iii) ΔDBC≅ΔACB (iv) CM=12AB
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Q2
In right triangle ABC, right angled at C, M is the mid-point of hypotenuse AB. C is joined to M and produced to a point D such that DM = CM. Point D is joined to point B (see the given figure). Show that:
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Q3
In right triangle ABC, right angled at C, M is the mid-point of hypotenuse AB. C is joined to M and produced to a point D such that DM = CM. Point D is joined to point B (see the given figure). Show that:
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[NCERT]
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Q4
In right triangle ABC, the right angle is at C, M is the mid-point of hypotenuse AB. C is joined to M and produced to a point D such that DM = CM. Point D is joined to point) B (see figure).
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Q5
In right triangle ABC, right angled at C, M is the mid-point of hypotenuse AB. C is joined to M and produced to a point D such that DM = CM. Point D is joined to point B (see the given figure). Show that: ΔAMC≅ΔBMD