Question

$y_{1}=sin(6π )sin(ωt)+sin(3π )cos(ωt)$

$y_{2}=cos(6π )sin(ωt)+sin(3π )cos(ωt)$ is:

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Updated on : 2022-09-05

Solution

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Correct option is B)

$=sin$ $ωtcos(3π )+cos$ $ωtsin3π $

$=sin(ωt+3π )$

Similarly for the second equation is:

$y_{2}=sin(ωt+6π )$

$y_{2}=sin(ωt+6π )$

Thus phase difference between the two waves is

$3π −6π =6π $

Solve any question of Oscillations with:-

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