The molarity of pure water is:

Question

Verified by Toppr

Answer 1

Formula:
$M o l a r i t y = \frac{N o o f m o l e s o f s o l u t e}{V o l u m e o f s o l u t i o n i n l i t r e}$
Step 1: To find the mass of water in one liter.
We know that,
Density of water = $1 g / m l$
or = $1 k g / L$
Therefore, the mass of $1 L$ of water will be:
$M a s s = D e n s i t y o f w a t e r \times V o l u m e M a s s = 1 \frac{k g}{L} \times 1 L M a s s = 1 k g = 1000 g$

Step 2: To find the molar mass of water
Molar mass of $H_{2} O$ = $2 \times H + 1 \times O$
Molar mass of $H_{2} O$ = $2 \times 1 + 1 \times 16$
Molar mass of $H_{2} O$ = $2 + 16$ = $18 g / m o l$

Step 3: To find the molarity in $1$ kg of water.
Moles in $1 k g$ of water $= \frac{m a s s}{m o l a r m a s s}$ $= \frac{1 0 0 0 g}{1 8 g / m o l} = 55.55 m o l$
Molarity of water = $= \frac{5 5 . 5 5 m o l e s}{1 L} = 55.55 M$

Final answer: Option $C$
Molarity of water is $55.5 M$

Answer 2

Formula:

$M o l a r i t y = \frac{N o o f m o l e s o f s o l u t e}{V o l u m e o f s o l u t i o n i n l i t r e}$

Step 1: To find the mass of water in one liter.

We know that,

Density of water =

1 g / m l

or =

1 k g / L

Therefore, the mass of

1 L

of water will be:

M a s s = D e n s i t y o f w a t e r \times V o l u m e M a s s = 1 \frac{k g}{L} \times 1 L M a s s = 1 k g = 1000 g

Step 2: To find the molar mass of water

Molar mass of

H_{2} O

=

2 \times H + 1 \times O

Molar mass of

H_{2} O

=

2 \times 1 + 1 \times 16

Molar mass of

H_{2} O

=

2 + 16

=

18 g / m o l

Step 3: To find the molarity in $1$ kg of water.

Moles in

1 k g

of water

= \frac{m a s s}{m o l a r m a s s}

= \frac{1 0 0 0 g}{1 8 g / m o l} = 55.55 m o l

Molarity of water =

= \frac{5 5 . 5 5 m o l e s}{1 L} = 55.55 M

Final answer: Option $C$

Molarity of water is $55.5 M$

The molarity of pure water is:

18

5.56

55.5

100

The molality of $648 g$ of pure water is:

Calculate the molarity of pure water using its density to be $1000 k g m^{- 3}$ .

The molarity of pure water at $4^{\circ} C$ is

Molarity of $720 g m$ of pure water is:

Calculate the molarity of pure water using its density to be 1000 kg $m^{- 3}$

Revise with Concepts

Concentration Terms: Molarity

Concentration Terms: Molality

The molarity of pure water is:

18

5.56

55.5

100

The molality of 648g of pure water is:

Calculate the molarity of pure water using its density to be 1000kgm−3.

The molarity of pure water at 4∘C is

Molarity of 720gm of pure water is:

Calculate the molarity of pure water using its density to be 1000 kg m−3

Revise with Concepts

Concentration Terms: Molarity

Concentration Terms: Molality

The molality of $648 g$ of pure water is:

Calculate the molarity of pure water using its density to be $1000 k g m^{- 3}$ .

The molarity of pure water at $4^{\circ} C$ is

Molarity of $720 g m$ of pure water is:

Calculate the molarity of pure water using its density to be 1000 kg $m^{- 3}$