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The molecules of a given mass of a gas have r.m.s velocity of 200ms1 at 270C and 1.0×105Nm2 pressure. When the temperature and pressure of the gas are respectively, 1270C and 0.05×105Nm2, the r.m.s. velocity of its molecules in ms1 is:
  1. 1002
  2. 4003
  3. 10023
  4. 1003

A
1002
B
10023
C
4003
D
1003
Solution
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We know that: vT

v200=400300

v=200×23=4003m/s

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