0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Question

The normal at $$\left( \dfrac { 2 }{ 5 } ,\dfrac { 4 }{ 5 } \right) $$ to the curve $$y=f(x)$$ intersects the curve agains at the point

A
$$\left( \dfrac { 8 }{ 5 } ,\dfrac { 4 }{ 5 } \right) $$
B
$$\left( \dfrac { 8 }{ 5 } ,-\dfrac { 4 }{ 5 } \right) $$
C
$$\left( \dfrac { 2}{ 5 } ,-\dfrac { 4 }{ 5 } \right) $$
D
None of these
Solution
Verified by Toppr

Correct option is A. $$\left( \dfrac { 8 }{ 5 } ,\dfrac { 4 }{ 5 } \right) $$

Was this answer helpful?
0
Similar Questions
Q1
The point $$A(2,2)$$ lies on the curve $$y = x^2 - 2x + 2$$. The normal to the curve at $$A$$ intersects the curve again at $$B$$. Find the coordinate of $$B$$.
View Solution
Q2

Consider the curvey2=2x and pointA(2,2). If the normal at Aintersects the curve again at point B and the tangent at A intersects the x-axis at C, then the area of āˆ†ABCis


View Solution
Q3
The normal to the curve 2x2+y2=12 at the point (2,2) cuts the curve again at
View Solution
Q4
The normal to the curve 2x2+y2=12 at the point (2,2) cuts the curve again at
View Solution
Q5
Tangent to a non-linear curve y=f(x), at any point on P intersects xaxis and yaxis at A and B respectfully. If normal to the curve y=f(x) at P intersects y=axis at C such that AC=BC, f(2)=3, then equation of curve is
View Solution