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Question

# The number of 4 digit numbers that can be formed with 0,1,2,3,5 which are divisible by 2 or 5 is841206053

A
120
B
84
C
60
D
53
Solution
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#### Considering 0,1,2,3,5 and non repetitions of digits.Number of four digit numbers divisible by 2 or 5 should contain 0,2 or 5 in the end of the number.→_ _ _ 5 Implies 4(3!) numbers.Now eliminating the numbers with 0 at the starting, we get4(3!)−3!=3(3!)=18. ...(i)Implies 4(3!) numbers.=24 ...(ii)Implies 4(3!)Eliminating the numbers with 0 at the starting, we get4(3!)−3!=3(3!)=18 ...(ii)Adding (i), (ii) and (iii), we get18+24+18=36+24=60

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