The number of atoms of Cr and O are 4-8times 10-10- and 9-6times 10-10- respectively- Its empirical formula is-Cr-2O-3CrO-2Cr-2O-4None of these

Question

Toppr Admin · Accepted Answer

Number of atoms of Cr - 4-8-xD7-1010Number of atoms of O - 9-6-xD7-1010-xA0-The ratio of number of atoms of Cr to O -xA0- 4-8-xD7-10109-6-xD7-1010-1-2Hence- empirical formula of the compound is CrO2

The number of atoms of Cr and O are $4.8 \times 10^{10}$ and $9.6 \times 10^{10}$ respectively. Its empirical formula is?
$C r_{2} O_{3}$
$C r O_{2}$
$C r_{2} O_{4}$
None of these

Number of atoms of Cr = $4.8 \times 10^{10}$
Number of atoms of O = $9.6 \times 10^{10}$
The ratio of number of atoms of Cr to O = $\frac{4.8 \times 10^{10}}{9.6 \times 10^{10}} = 1 : 2$

Hence, empirical formula of the compound is $C r O_{2}$

The number of atoms of Cr and O are 4.8×1010 and 9.6×1010 respectively. Its empirical formula is?Cr2O3CrO2Cr2O4None of these

Number of atoms of Cr = 4.8×1010Number of atoms of O = 9.6×1010 The ratio of number of atoms of Cr to O = 4.8×10109.6×1010=1:2Hence, empirical formula of the compound is CrO2

The number of atoms of Cr and O are $4.8 \times 10^{10}$ and $9.6 \times 10^{10}$ respectively. Its empirical formula is?
$C r_{2} O_{3}$
$C r O_{2}$
$C r_{2} O_{4}$
None of these

Number of atoms of Cr = $4.8 \times 10^{10}$
Number of atoms of O = $9.6 \times 10^{10}$
The ratio of number of atoms of Cr to O = $\frac{4.8 \times 10^{10}}{9.6 \times 10^{10}} = 1 : 2$

Hence, empirical formula of the compound is $C r O_{2}$