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Oxidation Number Method

Question

The number of moles of $K M n O_{4}$ that will be needed to react with one mole of sulphite ion in acidic solution is :
$\frac{2}{5}$
$\frac{3}{5}$
$\frac{4}{5}$
$1$

A

\frac{2}{5}

B

1

C

\frac{3}{5}

D

\frac{4}{5}

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Solution

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The balanced chemical reaction is as given below,

$2 M n O_{4}^{-} + 5 S O_{3}^{2 -} + 6 H^{+} \to 2 M n^{2 +} + 5 S O_{4}^{2 -} + 3 H_{2} O$

$5$ moles of $S O_{3}^{2 -}$ reacts with $2$ moles of $K M n O_{4}$ .

Hence, $1$ mole of $S O_{3}^{2 -}$ will react with $\frac{2}{5}$ moles of $K M n O_{4}$ .

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