The number of unpaired electrons in a paramagnetic diatomic molecule of an element with atomic number $16$ is:

Question

The number of unpaired electrons in a paramagnetic atom of an element with atomic number 16 is -

Toppr Admin · Accepted Answer

We use-xA0-x3C3-1s-2-x3C3-x2217-1s-2-x3C3-2s-2-x3C3-x2217-2s-2-2pz-2-x3C0-4-x3C0-x2217-2-Anti bonding pi molecular orbital has two unpaired electrons-

The number of unpaired electrons in a paramagnetic atom of an element with atomic number $16$ is :

We use $(σ 1 s)^{2}, (σ^{} 1 s)^{2}, (σ 2 s)^{2}, (σ^{} 2 s)^{2}, (2 p_{z})^{2}, (π)^{4}, (π^{*})^{2}$ .
Anti bonding pi molecular orbital has two unpaired electrons.

The number of unpaired electrons in a paramagnetic atom of an element with atomic number 16 is :

We use (σ1s)2,(σ∗1s)2,(σ2s)2,(σ∗2s)2,(2pz)2,(π)4,(π∗)2.Anti bonding pi molecular orbital has two unpaired electrons.

The number of unpaired electrons in a paramagnetic atom of an element with atomic number $16$ is :

We use $(σ 1 s)^{2}, (σ^{} 1 s)^{2}, (σ 2 s)^{2}, (σ^{} 2 s)^{2}, (2 p_{z})^{2}, (π)^{4}, (π^{*})^{2}$ .
Anti bonding pi molecular orbital has two unpaired electrons.