The outer electronic structure of lawrencium (atomic number $$103$$) is :
A
$$[Rn] \ 5f^{13}7s^27p^2$$
B
$$[Rn] \ 5f^{13}6d^{1}7s^17p^2$$
C
$$[Rn] \ 5f^{14}7s^17p^2$$
D
$$[Rn] \ 5f^{14}6d^{1}7s^2$$
Open in App
Solution
Verified by Toppr
Correct option is D. $$[Rn] \ 5f^{14}6d^{1}7s^2$$
Was this answer helpful?
1
Similar Questions
Q1
The outer electronic structure of lawrencium (atomic number $$103$$) is :
View Solution
Q2
The atomic number of the element having outer electronic configuration (3d)5(4s)1 is
View Solution
Q3
The outer electron configuration of Gd. (Atomic number 64):
View Solution
Q4
Question 41 In electron dot structure, the valence shell electrons are represented by crosses or dots (a) The atomic number is 17. Write its electronic configuration. (b) Draw the electron dot structure of chlorine molecule.
View Solution
Q5
An element X forms a unipositive ion with the electronic structure 2,8,8. What is the atomic number of X?
