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Question

The output Y of the logic circuit given above is:
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  1. ¯A+B
  2. ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯(¯A+B)A
  3. ¯A
  4. ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯(¯A+B)¯A

A
¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯(¯A+B)A
B
¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯(¯A+B)¯A
C
¯A+B
D
¯A
Solution
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Using the Boolean expression, we write the output for each logic gate as shown.
The output of signal A after passing through NOT gate is ¯A
The output of signals ¯A and B after passing through AND gate is ¯A.B
The output of signals ¯A.B and ¯A after passing through OR gate is ¯A+¯A.B

Thus the output signal of the logic circuit Y=¯A+¯A.B
Y=¯A(1+B)
Using 1+B=1 , we get Y=¯A.1
Y=¯A

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