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Question

The oxidation number of hydrogen varies from:
-1 to +1
0 to +1
0 to +2
-1 to 0

A

-1 to +1

B

0 to +1

C

-1 to 0

D

0 to +2

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Solution

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The electronic configuration of the hydrogen atom is $1 s^{1}$ . So, it can act as an electron acceptor to complete its' outer orbital as well as it can act as an electron donor to donate its' outermost electron to gain stability like metals.

In hydrides like $N a H$ , $H$ occurs in $- 1$ state.
In acids as well as oxides, $H$ occurs in $+ 1$ state.

Therefore its' oxidation state varies from $- 1$ to $+ 1$ .

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