The oxidation state of manganese in -K-2-Mn-O-4- is-5-6-4-7

Question

Toppr Admin · Accepted Answer

Potassium oxidation number is -1- Oxygen oxidation number is -x2212-2-For K2MnO4-2-1-oxidation number of Mn-4-x2212-2-02-Oxidation number of Mn-x2212-8-0Oxidation number of Mn-6-So answer is B-

The oxidation state of manganese in $K_{2} M n O_{4}$ is:
$+ 5$
$+ 6$
$+ 4$
$+ 7$

Potassium oxidation number is $+ 1$ , Oxygen oxidation number is $- 2$ .
For $K_{2} M n O_{4}$ :
$2 (+ 1) +$ oxidation number of $M n + 4 (- 2) = 0$
$2 +$ Oxidation number of $M n - 8 = 0$
Oxidation number of $M n = + 6$ .
So answer is B.

The oxidation state of manganese in K2MnO4 is:+5+6+4+7

Potassium oxidation number is +1, Oxygen oxidation number is −2.For K2MnO4:2(+1)+oxidation number of Mn+4(−2)=02+Oxidation number of Mn−8=0Oxidation number of Mn=+6.So answer is B.

The oxidation state of manganese in $K_{2} M n O_{4}$ is:
$+ 5$
$+ 6$
$+ 4$
$+ 7$

Potassium oxidation number is $+ 1$ , Oxygen oxidation number is $- 2$ .
For $K_{2} M n O_{4}$ :
$2 (+ 1) +$ oxidation number of $M n + 4 (- 2) = 0$
$2 +$ Oxidation number of $M n - 8 = 0$
Oxidation number of $M n = + 6$ .
So answer is B.