+ 5 and 0 (two S have +5 and the other two S have 0)
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Correct option is A)
O.N of S is X O.N of Na is +1 O.N of O is -2 Sum of all O.N is 2×+1+(4X)+(6)×−(2) 4X−10 is equal to 0 X equals to 10/4 which equals to 2.5
his compound must have sulfur atoms with mixed oxidation states. Since it is normal for sulfur to have oxidation states of -2, 0, +2, +4, and +6, it is most likely that there are three sulfurs with a +2 oxidation state and one sulfur that is +4. Hence option A is correct.