Question

The oxidation state of in is:

A

+2.5

B

+2 and +3 (two have +2 and two have +3)

C

+ 2 and +3 (three have +2 and one has +3)

D

+ 5 and 0 (two have +5 and the other two have 0)

Medium

Solution

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Correct option is A)

O.N of is
O.N of is
O.N of is -2
Sum of all O.N is
is equal to 0
equals to 10/4 which equals to 2.5
his compound must have sulfur atoms with mixed oxidation states. Since it is normal for sulfur to have oxidation states of -2, 0, +2, +4, and +6,  it is most likely that there are three sulfurs with a +2 oxidation state and one sulfur that is +4.
Hence option is correct.

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