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Standard XII
Chemistry
Molecular Orbitals of Carbon
Question
The paramagnetic behaviour of
B
2
is due to the presence of:
Two unpaired electrons in
π
b
M
O
Two unpaired electrons in
∗
π
M
O
Two unpaired electron in
∗
σ
M
O
Two unpaired electrons in
σ
b
M
O
A
Two unpaired electron in
∗
σ
M
O
B
Two unpaired electrons in
σ
b
M
O
C
Two unpaired electrons in
∗
π
M
O
D
Two unpaired electrons in
π
b
M
O
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Solution
Verified by Toppr
B
2
contains
5
+
5
=
10
e
−
=
σ
1
s
2
∗
σ
1
s
2
σ
2
s
2
∗
σ
2
s
2
π
2
p
1
x
≃
π
2
p
1
y
Due to the presence of
2
unpaired electrons, in
π
bonding orbitals,
B
2
shows paramagnetic behaviour.
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