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Question

The paramagnetic behaviour of B2 is due to the presence of:
  1. Two unpaired electrons in πbMO
  2. Two unpaired electrons in πMO
  3. Two unpaired electron in σMO
  4. Two unpaired electrons in σbMO

A
Two unpaired electron in σMO
B
Two unpaired electrons in σbMO
C
Two unpaired electrons in πMO
D
Two unpaired electrons in πbMO
Solution
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B2 contains 5+5=10e

=σ1s2σ1s2σ2s2σ2s2π2p1xπ2p1y

Due to the presence of 2 unpaired electrons, in π bonding orbitals, B2 shows paramagnetic behaviour.

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