The particle is executing S.H.M. on a line 4cm long. If its velocity at mean position is 12cm/sec, its frequency in Hz will be :
2π3
32π
π3
3π
A
2π3
B
π3
C
32π
D
3π
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Solution
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Amplitude=2cm=A
Velocity of SHM at mean position
=Aω
⇒12=Aω
12=2×ω⇒ω=6
Frequency =ω2π
⇒f=62π=3π
⇒f=3π
Option D.
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