The peak value of an alternating current is 5A and its frequency is 60Hz. Find its rms value and time taken to reach the peak value of current starting from zero.
2.536A;4.167ms
3.536A;15ms
6.07A;10ms
3.536A;4.167ms
A
3.536A;4.167ms
B
2.536A;4.167ms
C
3.536A;15ms
D
6.07A;10ms
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Solution
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The correct option is A3.536A;4.167ms The RMS value of the current is given as:
irms=i0√2=5√2=3.536A
The time period of the current is:
T=1f⇒160s
So, the current takes one-fourth of the time period to reach the peak value starting from zero .
t=14×60=4.167ms.
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