The perpendicular bisectors of the sides of △ABC meet at I. Then:
The perpendicular bisectors of the sides of a triangle ABC meet at I.
Prove that : IA = IB = IC.
Perpendicular bisectors of the sides AB and AC of a triangle ABC meet at O.
(i) What do you call the point O?
(ii) What is the distance OA, OB and OC called?
(iii) Does the perpendicular bisector of BC pass through O?
