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Question

The perpendiculars from the mid-point of BC to AB and AC are equal.

If the above statement is true then mention answer as 1, else mention 0 if false.

Solution
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Given: ABC, B=C
Let D be the mid-point on BC. DFAC and DEAB
Now, In BED and CFD
DEB=DFC (Each 90)
BD=CD (D is mid point of BC)
B=C (Given)
thus, DBEDCF (ASA rule)
Hence, DE=DF (By cpct)
Hence proved.

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